Optimal. Leaf size=167 \[ -\frac {35 \tanh ^{-1}\left (\frac {\sqrt {a} \cos (c+d x)}{\sqrt {2} \sqrt {a \sin (c+d x)+a}}\right )}{128 \sqrt {2} a^{5/2} d}+\frac {35 \sec (c+d x)}{96 a^2 d \sqrt {a \sin (c+d x)+a}}-\frac {35 \cos (c+d x)}{128 a d (a \sin (c+d x)+a)^{3/2}}-\frac {7 \sec (c+d x)}{48 a d (a \sin (c+d x)+a)^{3/2}}-\frac {\sec (c+d x)}{6 d (a \sin (c+d x)+a)^{5/2}} \]
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Rubi [A] time = 0.23, antiderivative size = 167, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {2681, 2687, 2650, 2649, 206} \[ \frac {35 \sec (c+d x)}{96 a^2 d \sqrt {a \sin (c+d x)+a}}-\frac {35 \tanh ^{-1}\left (\frac {\sqrt {a} \cos (c+d x)}{\sqrt {2} \sqrt {a \sin (c+d x)+a}}\right )}{128 \sqrt {2} a^{5/2} d}-\frac {35 \cos (c+d x)}{128 a d (a \sin (c+d x)+a)^{3/2}}-\frac {7 \sec (c+d x)}{48 a d (a \sin (c+d x)+a)^{3/2}}-\frac {\sec (c+d x)}{6 d (a \sin (c+d x)+a)^{5/2}} \]
Antiderivative was successfully verified.
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Rule 206
Rule 2649
Rule 2650
Rule 2681
Rule 2687
Rubi steps
\begin {align*} \int \frac {\sec ^2(c+d x)}{(a+a \sin (c+d x))^{5/2}} \, dx &=-\frac {\sec (c+d x)}{6 d (a+a \sin (c+d x))^{5/2}}+\frac {7 \int \frac {\sec ^2(c+d x)}{(a+a \sin (c+d x))^{3/2}} \, dx}{12 a}\\ &=-\frac {\sec (c+d x)}{6 d (a+a \sin (c+d x))^{5/2}}-\frac {7 \sec (c+d x)}{48 a d (a+a \sin (c+d x))^{3/2}}+\frac {35 \int \frac {\sec ^2(c+d x)}{\sqrt {a+a \sin (c+d x)}} \, dx}{96 a^2}\\ &=-\frac {\sec (c+d x)}{6 d (a+a \sin (c+d x))^{5/2}}-\frac {7 \sec (c+d x)}{48 a d (a+a \sin (c+d x))^{3/2}}+\frac {35 \sec (c+d x)}{96 a^2 d \sqrt {a+a \sin (c+d x)}}+\frac {35 \int \frac {1}{(a+a \sin (c+d x))^{3/2}} \, dx}{64 a}\\ &=-\frac {\sec (c+d x)}{6 d (a+a \sin (c+d x))^{5/2}}-\frac {35 \cos (c+d x)}{128 a d (a+a \sin (c+d x))^{3/2}}-\frac {7 \sec (c+d x)}{48 a d (a+a \sin (c+d x))^{3/2}}+\frac {35 \sec (c+d x)}{96 a^2 d \sqrt {a+a \sin (c+d x)}}+\frac {35 \int \frac {1}{\sqrt {a+a \sin (c+d x)}} \, dx}{256 a^2}\\ &=-\frac {\sec (c+d x)}{6 d (a+a \sin (c+d x))^{5/2}}-\frac {35 \cos (c+d x)}{128 a d (a+a \sin (c+d x))^{3/2}}-\frac {7 \sec (c+d x)}{48 a d (a+a \sin (c+d x))^{3/2}}+\frac {35 \sec (c+d x)}{96 a^2 d \sqrt {a+a \sin (c+d x)}}-\frac {35 \operatorname {Subst}\left (\int \frac {1}{2 a-x^2} \, dx,x,\frac {a \cos (c+d x)}{\sqrt {a+a \sin (c+d x)}}\right )}{128 a^2 d}\\ &=-\frac {35 \tanh ^{-1}\left (\frac {\sqrt {a} \cos (c+d x)}{\sqrt {2} \sqrt {a+a \sin (c+d x)}}\right )}{128 \sqrt {2} a^{5/2} d}-\frac {\sec (c+d x)}{6 d (a+a \sin (c+d x))^{5/2}}-\frac {35 \cos (c+d x)}{128 a d (a+a \sin (c+d x))^{3/2}}-\frac {7 \sec (c+d x)}{48 a d (a+a \sin (c+d x))^{3/2}}+\frac {35 \sec (c+d x)}{96 a^2 d \sqrt {a+a \sin (c+d x)}}\\ \end {align*}
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Mathematica [C] time = 0.46, size = 284, normalized size = 1.70 \[ \frac {\frac {48 \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )^5}{\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )}-57 \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )^4+114 \sin \left (\frac {1}{2} (c+d x)\right ) \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )^3-44 \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )^2+88 \sin \left (\frac {1}{2} (c+d x)\right ) \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )+\frac {64 \sin \left (\frac {1}{2} (c+d x)\right )}{\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )}+(105+105 i) (-1)^{3/4} \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )^5 \tanh ^{-1}\left (\left (\frac {1}{2}+\frac {i}{2}\right ) (-1)^{3/4} \left (\tan \left (\frac {1}{4} (c+d x)\right )-1\right )\right )-32}{384 d (a (\sin (c+d x)+1))^{5/2}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.71, size = 280, normalized size = 1.68 \[ \frac {105 \, \sqrt {2} {\left (3 \, \cos \left (d x + c\right )^{3} + {\left (\cos \left (d x + c\right )^{3} - 4 \, \cos \left (d x + c\right )\right )} \sin \left (d x + c\right ) - 4 \, \cos \left (d x + c\right )\right )} \sqrt {a} \log \left (-\frac {a \cos \left (d x + c\right )^{2} - 2 \, \sqrt {2} \sqrt {a \sin \left (d x + c\right ) + a} \sqrt {a} {\left (\cos \left (d x + c\right ) - \sin \left (d x + c\right ) + 1\right )} + 3 \, a \cos \left (d x + c\right ) - {\left (a \cos \left (d x + c\right ) - 2 \, a\right )} \sin \left (d x + c\right ) + 2 \, a}{\cos \left (d x + c\right )^{2} - {\left (\cos \left (d x + c\right ) + 2\right )} \sin \left (d x + c\right ) - \cos \left (d x + c\right ) - 2}\right ) + 4 \, {\left (245 \, \cos \left (d x + c\right )^{2} + 7 \, {\left (15 \, \cos \left (d x + c\right )^{2} - 32\right )} \sin \left (d x + c\right ) - 160\right )} \sqrt {a \sin \left (d x + c\right ) + a}}{1536 \, {\left (3 \, a^{3} d \cos \left (d x + c\right )^{3} - 4 \, a^{3} d \cos \left (d x + c\right ) + {\left (a^{3} d \cos \left (d x + c\right )^{3} - 4 \, a^{3} d \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 5.63, size = 751, normalized size = 4.50 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.24, size = 266, normalized size = 1.59 \[ -\frac {\left (210 a^{\frac {7}{2}}-105 \sqrt {a -a \sin \left (d x +c \right )}\, \sqrt {2}\, \arctanh \left (\frac {\sqrt {a -a \sin \left (d x +c \right )}\, \sqrt {2}}{2 \sqrt {a}}\right ) a^{3}\right ) \sin \left (d x +c \right ) \left (\cos ^{2}\left (d x +c \right )\right )+\left (-448 a^{\frac {7}{2}}+420 \sqrt {a -a \sin \left (d x +c \right )}\, \sqrt {2}\, \arctanh \left (\frac {\sqrt {a -a \sin \left (d x +c \right )}\, \sqrt {2}}{2 \sqrt {a}}\right ) a^{3}\right ) \sin \left (d x +c \right )+\left (490 a^{\frac {7}{2}}-315 \sqrt {a -a \sin \left (d x +c \right )}\, \sqrt {2}\, \arctanh \left (\frac {\sqrt {a -a \sin \left (d x +c \right )}\, \sqrt {2}}{2 \sqrt {a}}\right ) a^{3}\right ) \left (\cos ^{2}\left (d x +c \right )\right )-320 a^{\frac {7}{2}}+420 \sqrt {a -a \sin \left (d x +c \right )}\, \sqrt {2}\, \arctanh \left (\frac {\sqrt {a -a \sin \left (d x +c \right )}\, \sqrt {2}}{2 \sqrt {a}}\right ) a^{3}}{768 a^{\frac {11}{2}} \left (1+\sin \left (d x +c \right )\right )^{2} \cos \left (d x +c \right ) \sqrt {a +a \sin \left (d x +c \right )}\, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sec \left (d x + c\right )^{2}}{{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {1}{{\cos \left (c+d\,x\right )}^2\,{\left (a+a\,\sin \left (c+d\,x\right )\right )}^{5/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sec ^{2}{\left (c + d x \right )}}{\left (a \left (\sin {\left (c + d x \right )} + 1\right )\right )^{\frac {5}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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